Wave pattern and surface pressures
Drawn to scale, freestream horizontalResult
Second line in each tile: linear (Ackeret) theory for the same case and its difference from shock-expansion theory.
The three cases side by side
Same M∞, α and γ; each case keeps its own geometry. Click a row to switch.Surface-by-surface summary
Fi = pi ℓi is the absolute-pressure force per unit span on face i, acting normal to the face and into the body. ΔL′ and ΔD′ are its components perpendicular and parallel to the freestream. The p∞ parts cancel around the closed contour, so summing absolute forces and summing gauge forces give the same L′ and D′.
March the flow over each face
Pressures → forces → coefficients
Resolve the pressure forces in body axes first: N′ normal to the chord, A′ along it.
Both surfaces have length c and are parallel to the chord, so the plate carries no axial force:
Each face has length ℓ = c/cos δ, with ℓ cos δ = c and ℓ sin δ = t/2. The base of height t carries pb:
With face lengths ℓf (front) and ℓr (rear), ℓfcos ε1 = xm and ℓfsin ε1 = ℓrsin ε2 = t/2:
Then rotate by α into the wind axes and divide by \(q_\infty c\), with \(q_\infty=\tfrac12\rho_\infty V_\infty^2=\tfrac{\gamma}{2}p_\infty M_\infty^2\):
Sweep in angle of attack
Relations used
Turning toward the flow: oblique shock
For a compression of θ, find the weak-shock angle β from the θ–β–M relation, then use normal-shock relations on the normal component.
If θ exceeds θmax(M1, γ), no attached solution exists. The shock stands off the nose and this method no longer applies.
Turning away from the flow: Prandtl–Meyer expansion
An expansion is isentropic. Add the turning angle to the Prandtl–Meyer function and invert for M2.
Fan edges sit at the local Mach angle, μ = sin−1(1/M), measured from the local flow direction.
Pressure coefficient
Linear (Ackeret) theory check
For small angles every surface obeys \(C_p = 2\theta/\sqrt{M_\infty^2-1}\), with θ positive for compression. Integrating over the surfaces gives
The base term uses the same prescribed base pressure as shock-expansion theory; it is zero for pb = p∞.
For the symmetric diamond (xm = c/2) the bracket becomes α² + (t/c)².
Thickness adds drag but no lift in linear theory. The center of pressure of the lift sits at mid-chord, so \(c_{m,c/4}=-\alpha/\sqrt{M_\infty^2-1}\) for all three cases.
Assumptions and limits
- Two-dimensional, inviscid, calorically perfect gas: no skin friction, so cd here is wave drag (plus base drag if pb ≠ p∞).
- The leading-edge shocks must be attached. A detached bow shock invalidates the method.
- Each face has uniform pressure. On the diamond, the flow on each front face must stay supersonic so the shoulder turn is a Prandtl–Meyer fan.
- The wedge base pressure is an input, not a prediction.
- Trailing-edge waves and the slip line form downstream of the body. They do not change any surface pressure and are not needed for the forces.
- α is positive nose-up. cm is positive nose-up.
Face numbers: flat plate and wedge 1 = upper, 2 = lower, b = base; diamond 1 = upper front, 2 = upper rear, 3 = lower front, 4 = lower rear; ∞ = freestream.